I could probably do this if i tried, but I'm a lazy git. Oh, fine I'll be honest.

I suck !!!



Two questions:



A and B are numbers,

A=B+2

A+B=AB

Show that A and B are not integers.



The other one is a bit more complicated =/



To change temperatures measured in °C to °F you can use an exact formula or an approximate formula.



EXACT FORMULA: F = (9C)/5 + 32

APPROXIMATE FORMULA: F = 2C + 30



F is the temperature in °F

C is the tempetature in °C



At what temperature in °C do these formulae give an equal value for F?

You must show an algebraic method.



It's probably really easy once done but... meh

For the second one, the equation is actually:



Standardized testing made us do a problem with that, and the Celsius to Farenheit.

I enter the algebra room and my brain automatically shuts off. im numerophobic. i hate math. it gives me headaches. all this xy crap is useless in my life. lol. i was trying to read ur equations and i was like : o.O

lol we share the same dislike of maths.
lets us be married.

OH, and dewgong8, this is the actual formula


Someone help me... and I will love you forever! x

A=B+2
A+B=AB

Show that A and B are not integers.

(B+2)+B=(B+2)B substitution
2B+2=B^2+2B multiplying out
B^2=2 canceling 2B

so therefore b = square root of 2
and a = 2 + square root of 2
-----------------------------------------------
EXACT FORMULA: F = (9/5)C + 32
APPROXIMATE FORMULA: F = 2C + 30

At what temperature in °C do these formula give an equal value for F?

(9/5)C+32=2C+30 set them equal
(9/5)C+2=2C subtract 30 from both sides
2=(1/5)C subtract (9/5)C from both sides
C=10 degrees

Meh, it comes out the same either way.

no it doesnt. just admit you're wrong
your equation comes out to (9/5)C+ (288/5) which is more than 25 degrees off

Junk was perfect.



Also, if on the off chance you had to go further, you could say that since radical 2 (in other worlds, the square root of two) has a nonrepeating, nonterminating decimal and cannot be expressed as a simple fraction, it is an irrational number and therefore not an integer.

Junk I love you.
Thanks!!!

Substitute B+2 for A into equation 2.
(B+2)+B=B(B+2)
2B+2=B2+2B
2=B2
B would equal to the square root of 2, which is not an integer.

Do the same thing for A:
A=B+2 ---> B=A-2
Substitute A-2 for B into equation 2.
A+(A-2)=A(A-2)
2A-2=A2+2A
-2=A2
The square root of a negative number is an imaginary number, therefore it is also not an interger.




To find an equal value, the 2 F must be equal, therefore--->
(9C)/5 + 32=2C + 30
(9C)/5 + 32 - 2=2C + 30 - 2
(9C)/5 + 2 = 2C
((9C)/5 + 2)*5 = 2C * 5
9C +10 = 10C
10=C

There ya go, have fun

Somehow I don't think PSSAs are incorrect.

EDIT: Actually, it might be for just for conversion